CHEMICAL FAMILIES;
PATTERNS IN PROPERTIES
Objectives
By the end of this topic, the learner should be able to:
(a) Identify and write electron arrangement of alkali metals, alkaline earth metals, halogens and noble gases.
(b) State and explain the trends in physical properties of elements in group I, II, VII and VIII.
(c) State and explain the trends in reactivity of elements in group I, II, VII and VIII.
(d) Explain the similarities in chemical formulae of compounds of the elements in a group.
(e) Explain the unreactive nature of group VIII elements.
(f) Identify and write electron arrangement of period 3 elements.
(g) State and explain the trends in physical and chemical properties of the elements in period 3.
CHEMICAL FAMILIES;
PATTERNS IN PROPERTIES
Elements in the same group are said to belong to the same chemical family.
Trends in physical and chemical properties provide useful information in predicting the physical and chemical behaviour of the elements within a family.
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CHEMISTRY NOTES F1-4: LATEST NOTES
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CHEMISTRY NOTES F1-4: LATEST NOTES
The elements in group I of the periodic table are called Alkali metals.
These include, lithium, sodium, potassium, rubidium, caesium and francium. The electron arrangements of the first three alkali metals are as follows:
Lithium (L) : 2.1
Sodium (Na) : 2.8.1
Potassium (k) : 2.8.8.1
Each alkali metal atom has one electron in the outermost energy level. Down the group there is an increase in the number of occupied energy levels.
Task: Draw the atomic structure of the first 3 Alkali Metals.
It is not possible to measure the sizes of atoms and ions of elements in the laboratory due to their small size. The table below gives a summary of the atomic and ionic radii of the Alkali
Metals.
Atomic radiusis the distance between the centre of the nucleus of an atom and the outermost energy level occupied by an electron or electrons.
Discussion Questions
The atomic radii and ionic radii of the alkali metals increase down the group. This is because each alkali metal has one more occupied energy level than the preceding member in the group.
Lithium has two energy levels. Sodium has three while potassium has four. The outermost electron in a sodium atom is therefore further from the nucleus than the outermost electron in a lithium atom. This explains the increase in the atomic and ionic radii down the group.
The ionic radius of an alkali metal is less than its atomic radius.
An alkali metal forms an ion by losing the single electron from the outermost energy level. The resulting ion (cation) has one occupied energy level less than the corresponding atom.
When an atom loses an electron to form a positively charged ion, the remaining electrons experience greater nuclear attraction. The remaining energy levels move closer to the nucleus resulting in a reduction in the radius.
The table below shows some physical properties of alkali metals.
Ionization energyis the minimum energy required to remove an electron from the outermost energy level of an atom in the gaseous state.
Discussion Questions
State and explain the trends in the following properties down the group?
The alkali metals have a shiny metallic lustre when freshly cut. However, the surface quickly tarnishes. The surface tarnishes because of reacting with air.
The alkali metals are soft and easy to cut.
The softness and ease to cut increases down the group due to the decrease in the strength of the forces holding the atoms together as you move down the group.
The alkali metals have relatively low melting and boiling points.
The melting and boiling points decrease down the group due to the weakening of the forces holding the atoms together.
The strength of the forces holding atoms together depends on the size of the atoms. The larger the atoms, the weaker the force. Thus as the atomic radius increases the forces of attraction between the atoms weaken, hence the decrease in the melting and boiling points down the group.
Alkali metals are good conductors of heat and electricity. Conductivity in metals is due to the presence of delocalisedelectrons in the structure of the metal. Since they all have one electron in their outermost energy level, their conductivity is similar.
In metals, the electrons in the outermost energy level move randomly throughout the metallic structure. Since the electrons do not remain in one fixed position, they are said to be delocalised.
(v) 1st ionization energy
Down the group from lithium to potassium, the 1st ionization energy decreases. This means that less energy is needed to remove the electron from the outermost energy level of a potassium atom than a sodium atom and a lithium atom. This is because the effective force of attraction on the outermost electron by the positive nucleus decreases with increasing atomic size and distance from the nucleus.
Alkali metals react by losing the one electron from their outermost energy level to attain a stable electron configuration. Their reactivity increases down the group.
2Na(s) + 2H2O(l) 2NaOH(aq) + H2(g)
2NaOH(aq) + CO2 (g) Na2CO3 · H2O(s)
Sodium + Oxygen Sodium Oxide
4Na(s) + O2(g) 2Na2O(s)
Sodium + Oxygen Sodium peroxide
2Na(s) + O2(g) Na2O2(s)
Potassium + oxygen Potassium oxide
4K(s) + O2(g) 2K2O(s)
The observations made when alkali metals react with water are summarised in the table below.
| Metal | Observation when metal reacts with water | Rate of reaction |
| Lithium | Lithium floats in water. A colourless gas is produced. The gas does not ignite spontaneously. The resulting solution turns red litmus paper blue. | Vigorous |
| Sodium | Sodium metal darts on the water surface as it melts into a silvery ball. A hissing sound is produced. A colourless gas is produced which may ignite spontaneously. The solution formed is alkaline. | More vigorous |
| Potassium | The metal darts about on the surface of the water and melts into a silvery ball. A colourless gas is produced which spontaneously bursts into a flame. Potassium vapour burns with a lilac flame. The resulting solution is alkaline. | Explosive |
Metal + Water Metal hydroxide + Hydrogen
Lithium + Water Lithium hydroxide + hydrogen gas
2Li(s) + 2H2O(l) 2LiOH(aq) + H2(g)
Sodium + Water Sodium hydroxide + Hydrogen gas
2Na(s) + 2H2O(l) 2NaOH(aq) + H2(g)
Potassium + water Potassium hydroxide + Hydrogen gas
2K(s) + 2H2O(l) 2KOH(aq) + H2(g)
Alkali metals react with chlorine gas to form the corresponding metal chlorides. The reactivity of alkali metals with chlorine increases down the group. This is because of the increase in atomic radius which leads to increasing ease to lose the electron in the outermost energy level.
Task: Cut a small piece of sodium and place it in a deflagrating spoon. Warm it and quickly lower it into a gas jar containing chlorine. Record your observations.
Discussion Questions
When hot sodium metal is lowered into chlorine gas, the metal bursts into flame, white fumes of sodium chloride are formed.
Sodium metal + chlorine gas Sodium chloride
2Na(s) + Cl2(g) 2NaCl(s)
Lithium reacts less vigorously with chlorine while potassium reacts much more violently with chlorine than sodium.
Lithium + chlorine gas Lithium chloride
2Li(s) + Cl2(g) 2LiCl(s)
Potassium + chlorine gas Potassium chloride
2K(s) + Cl2(g) 2KCl (s)
Formulae of hydroxides, oxides and Chlorides of Alkali metals
Discussion Question
Explain the similarity in the chemical formulae of the compounds formed between alkali metal ions and hydroxides, oxides and chloride ions.
Each alkali metal ion combines with a single hydroxide ion to form the respective hydroxide namely; Lithium hydroxide (LiOH), sodium hydroxide (NaOH) and potassium hydroxide (KOH). This is because the valency of Group I elements is one. The same applies in the formation of lithium chloride (LiCl), sodium chloride (NaCl) and potassium chloride (KCl)
Two alkali metal ions combine with one oxide ion to form the corresponding oxide namely; Lithium oxide (L2O), sodium oxide (Na2O) and potassium oxide (K2O).
This is because the valency of oxygen is two. Therefore one oxygen ion requires two alkali metal ions to combine with to form the corresponding oxide.
Due to their high reactivity, alkali metals are not found as free elements. They are normally found in the combined state in the earths’ crust.
TiCl4(g) + 4Na(l) Ti(s) + 4NaCl(l)
The elements in group II of the periodic table are called alkaline earth metals.
They consist of beryllium, magnesium, calcium, strontium, barium and radium. The electron arrangement of the first three alkaline earth metals is as follows:
Beryllium (Be) ; 2.2
Magnesium (Mg); 2.8.2
Calcium (Ca) ; 2.8.8.2
An atom of an alkaline earth metal has two electrons in the outermost energy level.
Task: Draw the atomic structure of the first 3 Alkaline Earth Metals
The table below summaries the atomic and ionic sizes of the Alkaline Earth Metals.
Discussion Question
State and explain the trends in atomic and ionic sizes down the group
Among the alkaline earth metals, theatomic radius increases down the group as more energy levels are occupied.
Beryllium has the smallest atomic radius among the alkaline earth metals because it has the least number of occupied energy levels.
Group II elements form ions by losing the two electrons in the outermost energy level in order to attain a stable electron arrangement. The loss of two electrons in the outermost energy level accounts for the smaller ionic radius compared to the atomic radius of the corresponding atom.
| Ion | Electron arrangement |
| Be2+ | 2 |
| Mg2+ | 2.8 |
| Ca2+ | 2.8.8 |
Beryllium ion with only one occupied energy level is therefore the smallest ion.
The table below summarises the Physical Properties of Alkaline Earth Metals
Discussion Questions
(a) One cuts an alkaline earth metal?
A ductile material is one which can be drawn into a wire. Materials which can be hammered into sheets are said to be malleable. A brittle substance is one which is hard and likely to break.
Both magnesium and calcium are good conductors of heat and electricity due to the presence of delocalised electrons.
The melting and boiling points of beryllium are very high compared to other alkaline earth metals. This is because the beryllium atom is very small and the forces of attraction between the atoms are very strong.
Down the group the melting point and boiling points decrease. This is because in metals atoms are held together by forces of attraction between positive nuclei and delocalised electrons. As the atomic radius increase this attraction decreases because of the increasing distance from the positive nucleus to the delocalised electrons. This explains why the melting point and boiling point decreases down the group.
The first and second ionization energies decreases down the group. This is because the effective force of attraction on the outermost electron by the positive nucleus decreases with increasing atomic size and distance from the nucleus.
The first ionization energy for magnesium is the minimum amount of energy required to remove one electron from the outer most energy level.
Mg(g) Mg+(g) + e– (1st I.E. = 736 kJmol–1)
The second ionisation energy of magnesium is the minimum amount of energy required to remove a second electron from a magnesium ion with a single positive charge.
Mg2+(g) Mg2+(g) + e– (2nd I.E. = 1450 kJmol–)
Once an electron has been lost from an atom, the overall positive charge holds the remaining electrons more firmly. This then means that removing a second electron form the ion requires more energy than the first electron.
Discussion Questions
Magnesium burns in air with a blinding brilliant white flame forming a white solid. The white solid is a mixture of magnesium oxide and magnesium nitride.
Magnesium + Oxygen Magnesium oxide
2Mg(s) + O2(g) 2MgO(s)
Magnesium + nitrogen Magnesium nitride
3Mg(s) + N2(g) Mg3N2(s)
Calcium on the other hand burns with a faint orange-red flame forming a white solid, which is a mixture of calcium oxide and calcium nitride.
Calcium + Oxygen Calcium oxide
2Ca(s) + O2(g) 2CaO(s)
Calcium + Nitrogen Calcium nitride
3Ca(s) + N2(g) Ca3N2(s)
The trend in reactivity of the alkaline earth metals when burning in air is not clear due to the oxide coating on calcium.
Magnesium reacts slowly with cold water to form magnesium hydroxide and hydrogen gas bubbles of which stick on the surface of the metal. Magnesium hydroxide dissolves slightly in water to form an alkaline solution.
Magnesium + Water Magnesium hydroxide + Hydrogen gas
Mg(s) + 2H2O(I) Mg(OH)2(aq) + H2(g)
A steady stream of hydrogen gas is evolved when calcium reacts with cold water. A white suspension appears in the beaker due to the formation of calcium hydroxide which is sparingly soluble in water. The calcium hydroxide solution formed is alkaline.
Calcium + Water Calcium hydroxide + Hydrogen gas
Ca(s) + 2H2O (s) Ca(OH)2(aq) + H2(g)
The atomic radii increase from beryllium to calcium. Therefore, the two outer electrons in a calcium atom are more loosely held by the positive nucleus than the outer electrons in magnesium. This means that less energy is required to remove the outer electrons in calcium than in magnesium. Calcium is therefore more reactive than magnesium.
The order of reactivity of the alkaline earth metals increases down the group.
Magnesium reacts slowly with cold water. However, it reacts faster with steam.
To react magnesium with steam, Put some wet sand at the bottom of a test tube. Insert a clean piece of magnesium ribbon (5 cm) into the middle of the test-tube ensure that the coil touches the sides of the tube. Set up the apparatus as shown in below.
Heat the sand gently first, then heat the magnesium ribbon strongly until it glows, then continue to heat the wet sand to generate steam. Record your observations. Test any gas produced using a burning splint. Before the heating is discontinued, the delivery tube should be removed from the water.
Discussion Questions
Magnesium burns in steam with a white flame. A white solid is formed and a colourless gas is produced. A pop sound is produced when a burning splint is introduced into a test-tube containing the gas. Therefore the colourless gas is hydrogen.
Magnesium + Steam Magnesium oxide + Hydrogen
Mg(s) + H2O(g) MgO(s) + H2(g)
The sand is heated initially to drive out the air that would otherwise react with magnesium by generating some steam.
The delivery tube is removed from the water before heating is stopped at the end of the experiment to prevent sucking back as the apparatus cools.
A pop sound is produced when a burning splint is introduced into a test-tube containing the gas. Therefore the colourless gas is hydrogen.
Discussion Questions
When a burning piece of magnesium is lowered into a gas jar containing chlorine, the metal continues to burn with a brilliant white flame to form a white powder. The white ash formed is magnesium chloride.
Magnesium + Chlorine Magnesium chloride
Mg(s) + Cl2(s) MgCl2(s)
Calcium may not react steadily with chlorine. This is because a coating of calcium oxide is formed first when the metal is heated. However, under suitable conditions calcium may react with chlorine to form calcium chloride.
Calcium + Chlorine gas Calcium chloride
Ca(s) + Cl2(g) CaCl2(s)
Discussion Questions
There is effervescence when a piece of magnesium is placed in hydrochloric acid. The gas produced during the reaction produces a ‘pop’ sound when a burning splint is introduced to the mouth of the test tube. This shows that the gas produced is hydrogen.
Magnesium + Hydrochloric acid Magnesium chloride + Hydrogen gas
Mg(s) + 2HCl(aq) MgCl2(aq)+ H2(g)
Magnesium + Sulphuric acid Magnesium sulphate + hydrogen gas
Mg(s) + H2SO4(aq) MgSO4(aq) + H2(g)
Calcium reacts with dilute hyrdrochloric acid to produce hydrogen gas and calcium chloride.
Calcium + Hydrochloric acid calcium chloride + hydrogen gas
Ca(s) + 2HCl(aq) CaCl2(aq) + H2(g)
When sulphuric (VI) acid is used, the reaction quickly stops. This is due to to the formation of insoluble calcium sulphate which forms a coating on the surface of calcium metal preventing further reaction.
Calcium + Sulphuric acid Calcium sulphate + Hydrogen gas
Ca(s) + H2SO4 (aq) CaSO4(s) + H2(g)
All alkaline earth metals have a valency of two (2). Hence the chemical formulae of their compounds are similar.
Formation of hydroxides, oxides and chlorides of alkaline earth metals.
Both magnesium and calcium ions have a valency of 2. The hydroxide ion and chloride ion have a valency of 1. Therefore two hydroxide ions combine with one magnesium ion to form magnesium hydroxide, Mg(OH)2. Similarly, two chloride ions will combine with one magnesium ion to form magnesium chloride, MgCl2.
On the other hand, the oxide ion has valency of 2. therefore, one calcium ion combines with one oxide ion to form calcium oxide, CaO.
The word halogen is derived from the Greek word ‘halo’ meaning salt and ‘gen’ meaning producer. Halogen thus means salt producer. Halogens are non-metals in Group VII of the periodic table. Fluorine, chlorine, bromine and iodine are the first four members of the halogen group. The electron arrangement of fluorine and chlorine is as follows:
Fluorine 2.7
Chlorine 2.8.7
Task: Draw the atomic structure of the first 2 Halogens
The table below gives the atomic and ionic sizes of the Halogens.
Discussion Questions
The atomic and ionic radii of the halogens increase down the group. This is because of the increase in the number of occupied energy levels.
The atomic radius of a halogen atom is less than the radius of its ion.
For example, the atomic radius of a chlorine atom is less than the ionic radius of a chloride ion. This is because the chlorine atom has 17 protons in the nucleus attracting 17 electrons in the energy levels. The chloride ion has 17 protons in the nucleus attracting 18 electrons. The effect of the positive nucleus is thus lower. The reduction in the nuclear attraction is due to repulsive effect between the existing electrons and the incoming electron.
Chlorine can be prepared by the action of concentrated hydrochloric acid on potassium manganate (VII) (KMnO4) or Manganese (IV) oxide (MnO2). Heat is required when manganese (IV) oxide is used.
Set up for preparing chlorine gas
The table below gives a summary of the physical properties of halogens.
Discussion Questions
Fluorine and chlorine are gases at room temperature. Bromine is a volatile liquid while iodine is a solid.
Fluorine is pale yellow while chlorine is green-yellow. Bromine is a brown liquid while iodine is a shiny dark grey solid.
When a boiling tube containing chlorine gas or bromine vapour is inverted in water or tetrachloromethane, the level of the solution rises in the boiling tube.
The level of the solution rises more in tetrachloromethane than in water. The rise in water level is higher in the case of chlorine compared to bromine. This shows that chlorine is more soluble in water than bromine. Solubility of halogens in water therefore decreases down the group. All halogens are soluble in tetrachloromethane.
Iodine sublimes when heated to form a purple vapour. This is because the particles are held by weak forces which require little energy to break.
Halogens are non conductors of heat and electricity. This is because there are no delocalised electrons in their structures.
The melting and boiling points of halogens increase down the group.
Halogens exists as diatomic molecules. The forces of attraction between molecules (intermolecular forces) increase with the increase in the size of the molecules. Hence, the forces of attraction between molecules among the four halogens are strongest in iodine and weakest in fluorine.
It is not easy for non metals to lose electrons because the amount of energy required (ionisation energy) is very large. Therefore non metals do not easily form positively charged ions. Non metals therefore react by gaining electrons to form negatively charged ions.
Halogens have seven electrons in their outermost energy level. They react by gaining one electron to attain a stable electron configuration and form negatively charged ions. During ion formation, energy is released. The energy change for this process of electron gain is called electron affinity.
F + e– F– (Elctron affinity = –322 kJmol–1)
Cl + e– Cl– (Electron affinity = –349 kJmol–1)
Br + e– Br– (Electron affinity = –325 kJmol–1)
I + e– I– (Electron affinity = –295 kJmol–1)
Generally, the electron affinity decreases as the size of the atoms increases hence reactivity decreases down the group.
The reaction between iron and a halogen results in the formation of a salt.
The procedure below can be used to react halogens with metals. Pass a stream of dry chlorine gas over heated iron wool as shown below. Record your observations.
For bromine and iodine, heat the iron wool in a test-tube in which bromine and iodine vapour is generated and passed over the wool as shown below. The test-tube should be held with a test-tube holder. Alternatively, using a defragrating spoon, place hot iron wool into a gas jar of chlorine.
Discussion Questions
Chlorine reacts most vigorously with hot iron forming dark-brown crystals of iron (III) chloride. Hot iron glows in bromine vapour to form dark-red crystals of iron (III) bromide. Iodine vapour reacts slowly with hot iron to form grayish black crystals of iron (II) iodide. Iodine is not reactive enough to form a salt with iron.
The equations below represent the reactions which occur.
Iron + Chlorine Iron (III) chloride
2Fe (s) + 3 Cl2(g) 2FeCl3(s)
Iron + Bromine Iron (III) bromide
2Fe(s) + 3Br2(g) 2FeBr3(s)
Iron + Iodine Iron (II) iodine
Fe(s) + I2(g) Fel2(s).
Concentrated sodium hydroxide is used to react with excess chlorine to avoid emitting poisonous chlorine gas into the air.
Halogens react with heated zinc to form zinc salts.
Zinc + Chlorine Zinc chloride
Zn(s) + Cl2(g) ZnCl2(s)
Zinc + Bromine Zinc bromide
Zn (s) + Br (g) ZnBr2(s)
Zinc + Iodine Zinc iodide
Zn(s) + I2(g) ZnI2(s)
Other salts formed in the same method are MgCl2, AlCl3 and NaCl.
The reaction between chlorine and metals is more vigorous than that of bromine. The order of reactivity of the halogens with metals decreases down the group.
The ability of an atom to gain an electron in its outermost energy level decreases as the size of the atoms increase, hence the decrease in reactivity of halogens down the group.
To study the reaction between halogens and water, bubble chlorine through water in a conical flask for a few minutes using an experimental set-up as shown below.
Observe the colour of the resulting solution. Test the solution with litmus paper.
Discussion Questions
Chlorine dissolves in water to form chlorine water which is a mixture of hydrochloric acid and chloric (I) acid.
Chlorine + water Hydrochloric acid + Chloric (I) acid
Cl2(g) + H2O(g) HCl(aq) + HClO (aq)
When the chlorine water is tested with litmus paper, the blue one turns red, showing that the solution is acidic. Then the litmus papers are bleached (decolourised) immediately.
The bleaching action is a property of Chloric (I) acid. Chloric (I) acid is unstable and decomposes to form hydrochloric acid and an atom of oxygen. The oxygen atom then combines with the natural dye in the litmus papers to form a colourless compound.
Chlorine does not bleach dry litmus paper because chloric (I) acid cannot be formed in the absence of water. The bleaching action is only possible in the presence of water.
Chlorine water is yellow due to the presence of chloric (I) acid.
In sunlight, the chlorine water is decolourised due to the decomposition of chloric (I) acid to oxygen gas and hydrochloric acid by the sunlight.
This reaction does not take place in the dark.
The elements in group (VIII) of the periodic table are called noble gases. Noble gases are found as free atoms in nature and form about 1% of air. They include helium, neon, argon, krypton, xenon and radon. Argon is the most abundant and forms about 0.9% of air by volume.
Noble gases were initially called inert gases because they were thought to be unreactive.
Task: Draw the atomic structure of the first 3 noble gases
Electron Arrangements of the first three Noble Gases
Helium with only two electrons has one occupied energy level which is full. Hence it has a duplet. The rest have eight electrons in their outermost occupied energy level. Thus they have the octet.
Under normal conditions noble gases neither gain nor lose electrons. They are therefore stable and non reactive.
Group VIII elements are colourless monoatomic gases.
Discussion Questions
1.What happens to each of the following properties down the group?
Atomic radii increase down the group due to the increase in the number of energy levels. The increase in atomic radii down the group explains why the first ionization energy of the gases decreases down the group.
Noble gases have low melting and boiling points. This is because of the weak inter atomic forces of attraction between the atoms. However, as the atomic size increases down the group there is increase in strength of inter atomic forces of attraction between atoms. Hence the rise in melting and boiling points down the group.
Helium has a duplet electron arrangement while the others have an octet in their outermost energy level. Therefore they all have a stable electron arrangement. This explains the high ionization energies for all the elements.
2.Xenon takes part in some reactions. Explain.
Xenon has a large atomic radius. In xenon an electron in the outermost energy level is relatively far from the positive nucleus. It therefore has a low ionization energy compared to the other noble gases. For this reason, xenon takes part in some reactions.
The inert nature of the noble gases enables them to have a wide range of uses.
Elements in the same period have the same number of occupied energy levels. As you move across the period, the number of electrons in the outermost energy level increases by one. While the elements in the same group exhibit similar properties, those across a period show a gradual change in properties. This can be illustrated by considering elements in Period 3 from left to right.
The table below gives a summary of the physical properties of Elements in Period 3.
Discussion Questions
Sodium, magnesium and aluminium are good conductors of electricity.
2.Explain the trends in the electrical conductivity of the elements in period 3.
Sodium, magnesium and aluminium have delocalised electrons in their structures. These delocalised electrons are responsible for the conduction of electricity. Conductivity increases with increase in the number of delocalised electrons. Therefore, aluminium with three delocalised electrons from each atom in the structure has the highest electrical conductivity.
Phosphorus, sulphur, chlorine and argon are all made up of molecules and therefore are non-conductors of electricity.
Silicon is unique among the elements because it is a semi-conductor. Its electrical conductivity increases with increase in temperature.
Discussion Questions
The atomic radii of the elements gradually decrease across the period from left to right. This is explained by the increase in the nuclear charge across the period due to an increase in the number of protons. Although there is an additional number of electrons, they enter the same energy level. This means that the shielding effect remains the same as the nuclear charge increases. The forces of attraction between the nuclei of these elements and the electrons in the outermost energy levels progressively increase across the period. As a result, the electrons in the outermost energy level are pulled closer to the nucleus, thereby decreasing the size of the atoms across the period from sodium to chlorine.
Sodium, magnesium and aluminium have giant metallic structures. Therefore, they have strong metallic bonds. These bonds require a lot of energy to break hence high melting and boiling points. Silicon has giant atomic structure hence high melting and boiling points. The rest of the non-metals have molecular structures held together by weak Van der Waals forces which require little energy to break hence low melting and boiling points.
Aluminium contributes three electrons to the metallic lattice whereas sodium contributes only one. Also, due to the small size of the aluminium atom, the packing of the atoms is close. Therefore, the metallic bonds in aluminium are stronger than in sodium and magnesium, hence the higher melting and boiling points of aluminium.
Silicon has a giant atomic structure in which all the atoms are held together by strong covalent bonds. These need a lot of heat energy to break, hence the high melting and boiling points of silicon. In contrast, phosphorus and chlorine are molecular. The atoms in the molecules are held together by strong covalent bonds while the molecules themselves are held together by van der Waals forces which require little energy to break. Melting involves breaking the van der Waals forces.
Chlorine and argon exist as gases at room temperature. They have low melting and boiling points due to the presence of weak van der Waals forces. Chlorine is diatomic while argon is monoatomic.
Summary of reaction of period 3 elements with air, water and dilute acids.
Discussion Questions
Sodium + Oxygen Sodium oxide
4Na(s) + O2 (g) 2Na2O (s)
The sodium oxide produced in the reaction readily dissolves in water to form an alkaline solution
Sodium oxide + Water Sodium hydroxide
Na2O(s) + H2O(l) 2NaOH(aq)
Magnesium + Oxygen Magnesium oxide
2Mg (s) + O2(g) 2MgO(s)
The magnesium oxide produced in the reaction is slightly soluble in water. The solution formed is alkaline.
Magnesium oxide + water Magnesium hydroxide
MgO(s) + H2O(l) Mg(OH)2(aq)
Aluminium + Oxygen Aluminium oxide
4Al(s) + 3O2(g) 2Al2 O3(s)
The aluminium oxide is insoluble in water.
Silicon + Oxygen Silicon (IV) oxide
Si(s) + O2(g) SiO2(s)
Silicon (IV) oxide is insoluble in water.
Phosphorus + Oxygen Phosphorus (V) oxide
P4(s) + 5O2(g) 2P2O5(s)
Phosphorus (V) oxide readily dissolves in water to form an acidic solution.
Phosphorus (V) oxide + Water Phosphorus (V) acid
P2O5(s) + 3H2O(l) 2H3PO4(aq)
Sulphur + Oxygen Sulphur (IV) oxide
S(s) + O2(g) SO2(g)
The sulphur (IV) oxide gas readily dissolves in water to give an acidic solution of sulphuric (IV) acid, H2SO3, which is easily oxidized to sulphuric (VI) acid H2SO4.
Sulphur (IV) oxide + Water Sulphuric (IV) acid
SO2(g) + H2O(l) H2SO3(aq)
Sulphuric (IV) acid + Oxygen Sulphuric(VI) acid
2H2SO3(aq) + O2(g) 2H2SO4(aq)
The following trends in the elements of period 3 can be identified.
Discussion Questions
Sodium + Water Sodium hydroxide + Hydrogen
2Na(s) + H2O(l) 2NaOH(aq) + H2(g)
Magnesium + water Magnesium hydroxide + Hydrogen
Mg(s) + 2H2O(l) Mg(OH)2(aq) + H2(g)
Chlorine + water Hydrochloric acid + Hypochlorous acid
Cl2(g) + H2O(l) HCl(aq) + HOCl(aq)
Discussion Questions
Explain the trend in reactivity of the period 3 elements with dilute acids.
Magnesium + hydrochloric acid Magnesium chloride + Hydrogen gas
Mg(s) + 2HCl(aq) MgCl2(aq) + H2(g)
Magnesium + Sulphuric (VI) acid Magnesium sulphate + Hydrogen gas.
Mg(s) + H2SO4(aq) MgSO4(aq) + H2(g)
Aluminium + Hydrochloric acid Aluminium chloride + Hydrogen gas
2Al(s) + 6HCl(aq) 2AlCl3(aq) + 3H2(g)
2Al(s) + 3H2SO4(aq) Al2(SO)4 (aq) + 3H2(g).
Both chlorine and iodine are halogens. What are halogens? (1 mark)
Explain why there is general increase in the first ionization energies of the elements in period 3 of the periodic table from left to right. (2 marks)
Give a reason why helium is increasingly being preferred to hydrogen in weather balloons. (1 mark)
The grid below is part of the periodic table. Use it to answer the questions that follow, (the letters are not the actual symbols of the elements).
The ionization energies for three elements A, B and C are shown in the table below.
| Element | A | B | C |
| Ionisation energy (kJ /mole) | 519 | 418 | 494 |
Give the name of the product formed when magnesium reacts with phosphorus. (1 mark)
The diagram below represents part of the periodic table. Use it to answer the questions that follow.
| M | Q | |||||||
| T | V | W | ||||||
The table below gives some properties of three elements in group (VII) of the periodic table. Study it and answer the questions that follow.
| Element | Atomic No. | Melting Point (°C) | Boiling Point (°C) |
| Chlorine | 17 | -101 | -34.7 |
| Bromine | 35 | -7 | 58.8 |
| Iodine | 53 | 114 | 184 |
What name is given to elements which appear in group (II) of the periodic table? (1 mark)
Distinguish between ionisation energy and electron affinity of an element. (2 marks)
The grid below is part of the periodic table. Use it to answer the questions that follow. (the letters are not the actual symbols of the elements).
(ii) Name the bond type in the compound formed in b (i) above (1 mark)
(ii) Write an equation for the reaction that occurs when C in gaseous form is passed through a solution containing ions of element H (1 mark)
The table below shows properties of some elements A, B, C and D which belong to the same period of the periodic table. The letters are not the actual symbols of the elements.
| Element | A | B | C | D |
| MP (°C) | 1410 | 98 | -101 | 660 |
| Atomic radii (nm) | 0.117 | 0.186 | 0.099 | 0.143 |
| Electrical conductivity | Poor | Good | Non-conductor | Good |
Group: (½ mark)
Period: (½mark)
(i) The general name of these elements; (1 mark)
(ii) One use of these elements (1 mark)
The plots below were obtained when the atomic radii of some elements in groups I and II were plotted against atomic numbers.
Explain:
Identify a letter which represents an element in the table that could be calcium, carbon or sulphur. Give a reason in each case.
Reason____________ (½ mark)
Reason_____________ (½ mark)
Reason_____________ (½ mark)
(ii)Under the same conditions, gaseous neon was found to diffuse faster than gaseous fluorine. Explain this observation. (F=19.0; Ne=20.0) (2 marks)
The table below is part of the periodic table. The letters are not the actual symbols of the elements. Study it and answer the questions that follows.
| Elements | Compounds |
A crystal of iodine, heated gently in a test tube gave off a purple vapour.
Use the information in the table below to answer the questions that follow. The letters do not represent the actual symbols of the elements.
| Element | Atomic Number | Melting Point (°C) |
| R | 11 | 97.8 |
| S | 12 | 650.0 |
| T | 15 | 44.0 |
| U | 17 | -102 |
| V | 18 | -189 |
| w | 19 | 64.0 |
(i) S is higher than that of R; (1 mark)
(ii) V is lower than that of U. (2 marks)
(1 mark)
Table 1 shows the atomic numbers and the first ionisation energies of three elements. The letters are not actual symbols of the elements. Use it to answer the questions that follow.
Describe an experiment to show that group one elements react with cold water to form alkaline solutions. (3 marks)
Figure 2 is a section of the periodic table. Study it and answer the questions that follow. The letters do not represent the actual symbols of elements
(ii) Write the formulae of ions for elements in the same period. (1 mark)
(ii) How do the reactivity of elements J and K compare? Explain. (2 marks)
| Element | Formula of chloride | Nature of chloride solution |
| L | ||
| M |
(ii) The chloride of element M vaporises easily while its oxide has a high melting point. Explain. (2 marks)
Study the information in Table 3 and use it to answer the questions that follow.
| Elements | Na | Mg | Al | Si | P | S | Cl |
| Atomic Numbers | 11 | 12 | 13 | 14 | 15 | 16 | 17 |
| Atomic radii(nm) | 0.157 | 0.136 | 0.125 | 0.117 | 0.110 | 0.104 | 0.099 |
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