Chapter Seven
ELECTROSTATICS (II)
Forces between Charged Bodies
Quantity of charges
Fig. 7. J: Leaf divergence is proportional to amount of charge
Distance of separation
When a positively charged pith ball is brought gradually close to another positively charged suspended pith ball the deflection of the suspended ball increases.
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If one brings a negatively charged pith ball near the suspended one, the two attract and the deflection increases as the suspended ball is approached.
Electric Field Patterns
Electric fields have the following properties:
(i) The electric lines of force are directed away from positive charges and towards negative charges
(ii) Unlike charges attract while like charges repel.
Conclusion
Electric field lines:
(i) are directed away from a positive charge and towards the negative charge.
(ii) do not cross one another.
(iii) are parallel at a uniform field, widely spaced at weak fields, closely arranged at strong fields.
CHARGE DISTRIBUTION ON THE SURFACE OF A CONDUCTOR
To show charge distribution on surfaces of conductors
Different conductors are charged and the charges tested using proof plane at different point
Observations
Explanation and Conclusion
Charge distribution for the sphere is even
For pear-shaped conductors the charges are more concentrated at the sharp edge
Note:
The pear-shaped body, discharges faster than the spherical shape because of the high charge concentration at the sharp curvature which causes charge leakage.
The charge distribution for cuboids is shown in figure
Charge distribution on hollow conductors
A charged hollow conductor reveals that no charge is found on the inside surface.
The distribution of charge on a hollow conductor can be demonstrated using a cylindrical conductor. The cylindrical conductor is placed on an uncharged electroscope and a charged sphere on an insulating handle is lowered into it without touching
Using a negatively charged sphere equal and opposite charges are induced on inside and outside of the cylinder. The leaf of the electroscope diverges
If the sphere is made to touch the inner wall of the cylinder, the leaf remains diverged
When withdrawn and then tested for charges, is found to contain no charge (neutral).
Charges on Sharp Points
Lightning Arrestor
Example
A thundercloud which is positively charged on its base hangs over a tall building fitted with a lightning arrestor. Explain the action of the pointed edges of the lightning arrestor in such a situation.
Solution
CAPACITORS
The material medium can be air, plastic or glass and is known as the ‘dielectric‘. A parallel- plate capacitor is represented by the symbol below.
Types of Capacitors
Capacitors are used in electric circuits for various purposes. Different types have different insulators (dielectric), depending on their uses. There are three main types of capacitors, namely, paper capacitors, electrolytic capacitors and variable capacitors.
Paper Capacitors
Paper capacitors consist of two long strips of metal foil between which are thin strips of paper, which act as the dielectric. The ‘sandwich’ is tightly rolled to form a small cylinder so that the arrangement is essentially parallel-plate capacitor of large surface area, occupying only a small volume, see figure 7.19 (a) and (b).
Fig. 7.19: Paper capacitor
Electrolytic Capacitors
These are made by passing a direct current between aluminium foils with a suitable electrolyte (aluminium borate) soaked in a paper.
When the current is passed for sometime, a very thin film of aluminium oxide is formed on the anode (marked positive). This film is an insulator and therefore acts as the dielectric. Electrolytic capacitors have much higher capacitance than the paper types.
Note:
The positive terminal of the capacitor should be connected to the positive side of the circuit; otherwise the thin film of aluminium oxide will break down.
The maximum working voltage should not exceed the recommended, lest the dielectric layer becomes a conductor.
Variable Air Capacitors
Variable air capacitors consists of fixed metal vanes connected to a metal frame and movable metal vanes joined to the central shaft and turned by a control knob
When the control knob is turned, overlap area of plates varies and so does the capacitance. Variable air capacitors are used in radio receivers for tuning.
Other types of capacitors include the plastic, ceramic and mica capacitors but their construction
and operation is similar to that of a paper capacitor.
Charging and Discharging Capacitors
To charge a capacitor
Procedure
| Time (s) | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 | 90 |
| Current I (mA) | ||||||||||
| It |
Observation
The charging current is initially high but gradually reduces to zero, see figure 7.23.
Explanation
The graph of charge (it) against t is shown
The graph shows that charge increases with time and becomes a maximum when the capacitor is fully charged.
During charging, potential difference also develops across the plates of the capacitor, see figure 7.25.
(Practical kcse year 2013 and 2014)
As charge increases, the potential difference between the plates also increases.
When the charging current reduces to zero, the potential difference between the plates of the capacitor will be seen to be the same as the battery voltage.
A resistor in charging a capacitor increases time for charging the capacitor
Discharging a charged capacitor
The capacitor is connected through a resistor and the current noted with time
| Time t (s) | 0 | 10 | 20 | 30 | 40 | 50 | 60 | 70 |
| Current I (mA) |
Plot a graph of current I (mA) against time t (s).
Explanation
Capacitance
Note:
One farad is a very large unit of capacitance and in practice, smaller units such as microfarads
(µF), nanofarads (nF) and picofarads (pF) are used.
1 µF= 10-6F
1 nF = 10-9F
1 pF = 10-12F
Factors affecting capacitance of a parallel-plate capacitor
(i) Area of the plates that are overlapping: An increase in the area of an overlap of the plates decreases the potential difference between the plates, hence capacitance increases.
(ii) Distance between the plates and area overlapping: When the plates are moved closer to each other but not touching, it results in decrease in electric potential between the plates and hence capacitance of the plates is increased.
(iii) Dielectric used between the plates:
When an insulating material medium is used, the potential difference between the plates decreases. A decrease in potential difference shows an increase
It follows that capacitance is directly proportional to the area of overlap and inversely proportional to the distance of separation. It also-depends on the nature of the dielectric.
So, C = ƹA/d where ƹ is a constant dependent on the medium between the plates and is called permittivity of the insulating material. If the plates are in vacuum, the constant is denoted by ƹo (epsilon nought) and its value is 8.85 x 10-12 Fm-1.
Example 1
Two plates of a parallel-plate capacitor are 0.6 mm apart and each has an area of 4 cm2. Given that the potential difference between the plates is 100 V, calculate the charge stored in the capacitor. (Take ƹo = 8.85 X 10-12 Fm-I)
Solution
Combinations of Capacitors
Just like resistors, capacitors can be combined in series or parallel to provide an effective value.
Capacitors in Series
Consider the series arrangement of capacitors in figure 7.30.
CAPACITORS IN PARALELL
Parallel arrangement
In the parallel arrangement, all capacitors have the same potential difference across them.
Let the potential difference across them be equal to V and Q1 Q2 and Q3 be the charge on each of the capacitors. The total charge;
Q T=Q1 +Q2+Q3 Q1 = C1V, Q2 = C2V and Q3= C3V
Therefore, Q = C1 V + C2 V + C3 V
Thus, Q/V = C1 + C2 + C3
But Q =C
V
So, C = C1 + C2 + C3, where C is the combined capacitance. In case of n capacitors of equal capacitance C1‘ the combined capacitance C = nC1
Example 2
Three capacitors of capacitance 1.5µF, 2 µand 3 µF are connected to a potential difference
of 12.0 V as shown in figure 7.32. Find:
(a) the combined capacitance.
(b) the total charge.
(c) the charge on each capacitor.
(d) the voltage across the 2 F capacitor.
(More examples in KCSE mirror page 211-213)
(a) Identify the factors that affect the capacitance of a capacitor.
(b) (i) On the set of axis show how the charge of a capacitor varies with time as a capacitor discharges.
Time, it
(ii) Draw a simple circuit to show how a capacitor can be discharged.
(c) Show that for two capacitors C1 and C2 arranged in series the effective capacitance CT is given by the relation:
Energy Stored in a Charged Capacitor
Energy stored in a capacitor is in form of electrical potential energy. The energy may be converted to heat, light or other forms.
A plot of potential difference V against charge Q for a charging capacitor gives a straight line through the origin, as
The area of ΔOAB =1/2 QV
But QV = work done in moving a charge Q through a potential difference of V volts. This is the energy stored in a charged capacitor.
Work done (W) = average charge x potential difference
= ½QV
= ½CV² (since Q = CV)
= Q²/2C(since V =Q/V)
Note that slope of graph yields =capacitance
ExampleS
A 2 µF capacitor is charged to a potential difference of 120 V. Find the energy stored in it.
Solution
W = ½CV2
= ½ x 2 x lQ-6 X 1202
= 1.44 X 10-2 J
Example 6
A 20 µF capacitor is charged to 60 V and isolated. It is later connected across an uncharged 100 µF capacitor. Calculate the final potential difference across the combination.
Solution
Let C1 = 20 µF. C2 = 100 µF.
V=60V
Let Q be the initial charge on C1
Q = V1C1
Q= 60x20x 10-6C
= 1.2 X 10-3C
When the two capacitors are connected in parallel. the potential difference across them is the same, say V E. Also, Q = QI + Q2‘ where QI and Q2 are the charges on the first and second
capacitors respectively.
But Q = C1VI, Q2 = C2V2
VI =V2=V
Q = C1VI + C2V2
= V(CI + C2)
1.2 x 10-3 = V x 120 x 1O-6F
V = 1.2 X 10-3
120 X 10-6
=l0V
Example 7
A 5 µF capacitor is charged to a potential difference of 200 V and isolated. It is then connected in parallel to a 10 µF capacitor. Find:
(a) the resultant potential difference.
(b) the energy stored before connection.
(c) energy in the two capacitors after connection. Is the energy conserved? Explain your answer.
Solution
(a) When the 5µF capacitor is charged to 200 V, it will acquire a charge;
Q = CV
=5x 10-6 x200
= 1.0 x 10-3 C
Let VI be the resultant potential. IfCI = 5µF and C2 = 10 µF, then;
C\V\ + C2V\ = 1.0 X 10-3
V – 1.0 X 10-3
C1 +C2
_ 1.0 x 10-3
– 15 X 10-6
= 66.7V
(b) Energy stored before connection = ½ CV2
= ½ x 5 x 10-6 X 2002
= 0.1 J
(c) Energy in the two capacitors = ½ x 5 X 10-6 X 66.72 + ½ x 10 X 10-6 X 66.72
= 1 X 66.72 (15 x 10-6)
= 0.03336 J
The energy is not conserved. Some of it is converted into heat in the connecting wires.
Applications of Capacitors
Capacitors have extensive uses. Some of these are described below.
When converting a.c. to d.c. using a diode, d.c. voltages appear varying from minimum to maximum. To maintain a high d.c. voltage, capacitors are included in the circuit.
A capacitor is included in the primary circuit of induction coil to eliminate sparking at the contacts.
In the tuning circuit of a radio receiver, a variable capacitor is connected in parallel to an inductor. When the capacitance of the variable capacitor is varied, the electrical oscillations between the capacitor and the inductor changes. If the frequency of oscillations is equal to frequency of the radio signal at the aerial of the radio, that signal is received.
Capacitors are used in delay circuits designed to give intermittent flow of current in car indicators.
A capacitor is included in a flash circuit of a camera. It is easily charged by a cell in the circuit. When in use, the capacitor discharges instantly to flash.
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