NAME……………………………………………………………..ADM/NO……………………
DATE…………………………. ………………… ………….CLASS……………………………
JOINT EXAMINATIONS
FORM 2
TERM THREE
PHYSICS 232
TIME: 2HRS
INSTRUCTIONS TO STUDENTS
| SECTION | QUESTION | MAXIMUM SCORE | CANDIDATE’S SCORE
|
| A | 1-12 | 25 | |
| B | 13-18 | 55 | |
| TOTAL | |||
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SECTION A (25 MARKS)
Answer all questions in the spaces provided
Determine the actual thickness of the object. (2mks)
(3mks)
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SECTION B (55 MARKS)
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(b) In an experiment to verify Hooke’s law, a piece of rubber was fixed to a rigid support and the other end pulled with a force of ranging magnitude. The values of force and the extension were recorded as in the table below:-
| Force (N) | 0 | 0.20 | 0.55 | 0.75 | 1.00 | 1.30 | 1.40 |
| Extension(cm) | 0 | 1.5 | 2.5 | 3.5 | 4.5 | 6.0 | 7.0 |
(5mks)
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(b) The height of a mercury barometer at a particular place is 70cm. given that the density of mercury is 13600kgm3, determine;
(i) The atmospheric pressure at the place. (3mks)
(ii) The height of a water barometer at the same place. (Density of water=1g/cm3) (2mks)
(iii) Give a reason why mercury is preferred as a barometric liquid. (1mks)
(c) Calculate the minimum pressure a block of dimensions 3cm by 10cm by 15cm and mass 12kg could exert on a horizontal surface. (3mks)
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Given that the speed of the wave is 10m/s. With reference to this wave motion, determine;
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(b) A building standing 200m from a pinhole camera produces on the screen of the camera an image 2.5cm and high 5.0cm behind the pinhole.
Determine the actual height of the building (3mks)
(c) An object of height 2.0cm is placed 5.0cm in front of a convex mirror of focal length 10.0cm
(i) On the grid provided, draw to scale a ray diagram to locate the position of the image.(4mks)
(ii) State two applications of concave mirrors (2mks)
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(b) A uniform metal rod of length 80cm and mass 3.2kg is supported horizontally by two vertical spring’s balances C and D. Balance C is a 20cm from one end while balance D is 30cm from the other end. Find the reading on each balance. (4mks)
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NAME……………………………………………………………..ADM/NO……………………
DATE…………………………. ………………… ………….CLASS……………………………
JOINT EXAMINATIONS
FORM 2
TERM THREE
PHYSICS 232
TIME: 2HRS
MARKING SCHEME
SECTION A (25 MARKS)
Answer all questions in the spaces provided
Determine the actual thickness of the object. (2mks)
Reading shown is 3.50
+ 0.01
3.51mm
Actual thickness = 3.51
+ 0.19
3.70mm
(3mks)
n =– 1 9=– 1
Ѳ=
=360
Anomalous expansion of water is defined as the unusual behavior of water in which it contracts when heated and expands when cooled between 0 and 40C
Pipes carrying steam are fitted with loops or expansion joints to allow for expansion when steam is passing through them and contraction when they are cooledFixing of Railway Line
A modern method of allowing for expansion and contraction in railways is to plane slant the rails so that they overlap
They are loosely fixed to allow for contraction. Telephone or electric wires appear to be shorter and taut in the morning. When it is hot, the wires appear longer and slackened
In bridges made of steel girders, one end is fixed and the other end placed on rollers to allow for expansion and contraction.
1
Mass on the earth’s surface = 600
10
= 60Kg
Value of g in the other planet = 450
60
= 7.5N/Kg
Photocopying
Q=It
200=I×0.6×60
I=
=5.556A
The vessel is placed on a wire gauZe because the gauZe is a good conductor of heat it therefore spreads the heat to a large area of the vessel.Without gauze heat will concentrate at one point which may lead to uneven expansion of glass hence break.
T=Ѳ +273
234= Ѳ+273
Ѳ= 234-273= -39c
SECTION B (55 MARKS)
For a helical spring or other elastic material, the extension is directly proportional to thestretching force, provided elastic limit is not exceeded.
(b) In an experiment to verify Hooke’s law, a piece of rubber was fixed to a rigid support and the other end pulled with a force of ranging magnitude. The values of force and the extension were recorded as in the table below:-
| Force (N) | 0 | 0.20 | 0.55 | 0.75 | 1.00 | 1.30 | 1.40 |
| Extension(cm) | 0 | 1.5 | 2.5 | 3.5 | 4.5 | 6.0 | 7.0 |
(5mks)
Plotting=2mk
Scale=1mk
Line=1mk
Axes= 1mk
(3mks)
K = F/E
Gradient = 0.75 – 0.2
3.5 – 1.0
= 0.5
2.5
= 0.2N/cm
1.3 N -check on student graph where the straight line starts a bend
-must be incompressible
-should not corrode the parts of break system
-have high boiling point
-have low freezing point
(b) The height of a mercury barometer at a particular place is 70cm. given that the density of mercury is 13600kgm3, determine;
(i) The atmospheric pressure at the place. (3mks)
Pa = 0.7×13600×10
=95200N/m2
(ii) The height of a water barometer at the same place. (Density of water=1g/cm3) (2mks)
95200=h×1000×10
h =
=9.52m
(iii) Give a reason why mercury is preferred as a barometric liquid. (1mks)
Mercury is much denser than water. It also supports a small and measurable column
(c) Calculate the minimum pressure a block of dimensions 3cm by 10cm by 15cm and mass 12kg could exert on a horizontal surface. (3mks)
Pmin=
=8000N/m2
Transverse waves, the vibration of the particles is a right angles to the direction of wave travel while longitudinal waves, the vibration of the particles is in a direction parallel to the direction of the wave travel.
b)The figure below shows a wave form in a string.
Given that the speed of the wave is 10m/s. With reference to this wave motion, determine;
50-10= 40m
5m
f= velocity/wavelength
=10/40 = 0.25Hz
t= 1/f =1/0.25 = 4s
Rectilinear propagation of light/light travels in a straight line
(b) A building standing 200m from a pinhole camera produces on the screen of the camera an image 2.5cm high 5.0cm behind the pinhole.
Determine the actual height of the building (3mks)
hi = v
ho u
ho =2.5 x 20000
5
= 10000cm or 100m
(c) An object of height 2.0cm is placed 5.0cm in front of a convex mirror of focal length 10.0cm
(i) On the grid provided,draw to scale a ray diagram to locate the position of the image.(4mks)
-shaving mirrors
-By dentist to examine teeth
A body is said to be in a stable equilibrium if it returns to the original position after being displaced slightly.
(b) A uniform metal rod of length 80cm and mass 3.2kg is supported horizontally by two vertical spring’s balances C and D balance C is also from one end while balance D is 30cm from the other end. Find the reading on each balance (4mks)
When pivot at C:
Then C.M = (30 x 32) Ncm
A.C.M = 50D
C.M = A.C.M =>
D = 19.2N
C + D = 32N
C = 32 – 19.2
= 12.8N
Reading on C = 12.8N
Reading on D = 19.2N
When circuit is closed, soft iron coregets magnetized and attracts the soft iron ammarture.The hammer being attached to the armature thus strikes the gong. the contacts breaks, core looses magnetism and armature returns to normal position.The process repeats.
When a straight conductor is held with right hand,with thumb showing the direction of current then the fingers show direction of magnetic field
AV= constant / A1V1=A2V2
a-area v- velocity
A1= 22/7*2.5*10-4
A2= 22/7* 1.5*10-4
A1V1=A2V2
V2= A1V1/A2
22/7*2. 52*10-4 *1)/22/7* 1.52*10-4
=2.778M/S
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