Name………………………………………………… adm no. ……………class…….
School …………………………………………………
231/1
BIOLOGY
PAPER 1
Time: 2 HOURS
KASSU JET EXAMINATION
231/1
BIOLOGY PAPER 1
Time: 2 HOURS
INSTRUCTIONS TO CANDIDATES
BIOLOGY FORM ONE SUMMARIZED NOTES
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FOR EXAMINERS USE ONLY
| Question | Maximum score | Candidate’s score |
| 1-29 | 80
|
This paper consists of 13 printed pages. Candidates should check the question paper to ascertain that all the pages are printed as indicated and no questions are missing
(2marks)
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| A |
| B |
| D |
(i) Name the part labelled A and B. (2 marks)
A ………………………………………………………………………………………………
C ………………………………………………………………………………………………
(ii) State two ways in which structure D is adapted to its functions. (2 marks)
………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
(iii) List two ways of preventing gingivitis. (2 marks)
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| Distance along the gill plates |
| % saturation of oxygen |
| Water |
| Blood |
(a) (i) Name the type of blood flow shown in the gill plate. (1mark)
……………………………………………………………………………………………… (ii) Explain the advantage of the type of flow named in a (i) above (2marks)
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(b) State two organs in humans which display the type of flow named in a (i) above (2marks)
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(c) State two ways in which floating leaves of aquatic plants are adapted to gaseous exchange (2marks) ………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
C51H98O6 + 145O2 ——- X CO2 + 98 H2O + energy
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State its name……………………………………………………………………….. (1mark)
How does this differ from growth in humans? (1mark)
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Name
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Function
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(a) Suggest the sampling method described above. (1 mark)
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(b) What are the disadvantages of this method? (2 marks)
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| Leaf surface | A | B | |
| Number of stomata
| Upper leaf surface | 20 | 5 |
| Lower leaf surface | 0 | 15 | |
| Surface area
| 25 cm2 | 18cm2 |
Identify with reasons the habitats of the plant from which the leaves were obtained.
Leaf A: (2 marks)
Habitat ……………………………………………..….…………..…………..
Reason ……………………..………………….…..….….…..……………….
………………………………………..………………………………
Leaf B: (2 marks)
Habitat ………………………………………………………………………………
Reason ………………………………………………………………………………
……………………………………………………………………………
(i) Trichomoniasis.
………………………………………………………………………………………………
(ii) Gonorrhea
………………………………………………………………………………………………
(i) Name the part labelled G. (1 mark)
………………………………………………………………………………………………
(ii) State two functions of structure labelled E. (2 marks)
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(b) Name the plant hormone that induces fruit ripening. (1 mark) ………………………………………………………………………………………………
(i) Name the type of metamorphosis in the above specimen. (1 mark)
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(ii) Give any two advantages of the above metamorphosis. (2 marks)
………………………………………………………………………………………………………………………………………………………………………………………………
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(ii) Name the cell organelle in which Carbon (IV) oxide combines with water to form a complex organic compound takes place (1 mark)
………………………………………………………………………………………………
(a) Which factor was being investigated in the experiment? (1 mark)
………………………………………………………………………………………………
(b) Which food test was carried out? (1 mark)
………………………………………………………………………………………………
(c) State the results of the food test. (1 mark)
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………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………
X
………………………………………………………………………………………………………………………………………………………………………………………………
V
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State the biological significance of the stage represented on the diagram above (1mark)
……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………….
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……………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………………..
c)Protogyny
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Name………………………………………………… adm no. ……………class…….
School …………………………………………………
231/1
BIOLOGY
PAPER 1
Time: 2 HOURS
KASSU JET EXAMINATION
231/1
BIOLOGY PAPER 1
Time: 2 HOURS
Sept 2021
INSTRUCTIONS TO CANDIDATES
FOR EXAMINERS USE ONLY
| Question | Maximum score | Candidate’s score |
| 1-29 | 80
|
This paper consists of 13 printed pages. Candidates should check the question paper to ascertain that all the pages are printed as indicated and no questions are missing
(2marks
In plants growth occurs at meristematic tissues only ;while in animals growth occurs all over the body ;
Reabsorbtion of sugars and some salts in the kidney
Absorption of digested food from the alimentary canal into the blood stream.
Excretion of waste products from body cells.
cyanide is an enzyme inhibitor, it affects the rate of active transport
(i) Name the part labelled A and B. (2 marks)
A Enamel
B Gum
(ii) State two ways in which structure D is adapted to its functions. (2 marks)
– Contains blood vessels which supplies food nutrients and oxygen and remove carbon IV oxide and nitrogenous waste products;
– Contains nerve endings for sensitivity;
(iii) List two ways of preventing gingivitis. (2 marks)
– Regular brushing of teeth;
-Proper exercise of the teeth by eating tough fibrous food;
-Eating foods that are rich in vitamin C
(a) (i) Name the type of blood flow shown in the gill plate. (1mark)
Counter current flow
(ii) Explain the advantage of the type of flow named in a (i) above (2marks)
Creates a steep diffusion gradient; that enhances the rate of gaseous exchange across the gill filaments/ increases rate of gaseous exchange; through diffusion (Rej increases rate of gaseous exchange/enhances gaseous exchange alone
(b) State two organs in humans which display the type of flow named in a (i) above Kidney; Placenta; Ileum (2marks)
(c) State two ways in which floating leaves of aquatic plants are adapted to gaseous exchange (2marks)
– Stomata found only on upper epidermis to allow efficient gaseous exchange;
– Presence of large air-spaces/aerechyma tissue to enable floating and storage of air;
– Lack cuticle to enhance gaseous exchange;
C51H98O6 + 145O2 ——- X CO2 + 98 H2O + energy
Volumetric relationship between Carbon (IV) oxide produced and oxygen consumed
R.Q = CO2 produced
O2 used up
R.Q = 102/145
R.Q = 0.7
Fat/ Lipid
State its name sigmoid curve (1mark)
How does this differ from growth in humans? (1mark)
In humans it’s continuous from time of birth to maturity when it slightly tails off while for
this phylum it’s discontinuous /in intervals with shedding of exoskeleton
Provides the seeds with enough time for dispersal so that they can germinate in suitable environment
Enables seeds to survive during adverse seeds to survive during adverse environmental conditions
The embryo has time to develop until favourable conditions are available
Decrease in oxygen and increase in carbon(1V)oxide
Germinating seeds respire using oxygen and release carbon(IV)oxide
Increases yields in plants
Cause early maturity in plants
Enhance resistance to pest, disease and drought
A cross between an offspring with one of its parents
Name
Cilia
Function
Propel mucus or a fertilised ovum
Trachea and oviduct
Cigarettes contain tar which impairs/inhibit the action of cilia in the respiratory tract leading to cancer.
a
B and Rhesus antigens
Plants reuse some of their waste products;
Plants produce their waste products slowly compared to animals that produce slowly ;
Diffusion
Transpiration
Guttation
Exudation
Deposition ( any two)
(a) Suggest the sampling method described above. (1 mark)
Capture recapture method
(b) What are the disadvantages of this method? (2 marks)
–Some organism may die during the study period;
-The mark may come the out during the study period;owtt
| Leaf surface | A | B | |
| Number of stomata
| Upper leaf surface | 20 | 5 |
| Lower leaf surface | 0 | 15 | |
| Surface area
| 25 cm2 | 18cm2 |
Identify with reasons the habitats of the plant from which the leaves were obtained.
Leaf A: Habitat Fresh water; (1 mark)
Reason; Maximum number of stomata on the upper leaf surface for quick loss of excess water by transpiration; (1 mark)
Leaf B: Habitat: Savannah/ Rain forest; (1 mark)
Reason : More stomata on loer surface than on the upper to reduce the surface area exposed to excessive loss of water by transpiration
(1 mark)
(i) Trichomoniasis.
Trichomonas vaginalis
(ii) Gonorrhea
Neisseria gonorrhoea
(i) Name the part labelled G. (1 mark)
Pollen tube;
(ii) State two functions of structure labelled E. (2 marks)
-Fuse with the egg cell nucleus to form zygote
–Fuse with polar nuclei to form a triploid endosperm nucleus;
A type of asexual reproduction in insects where eggs produced without being fertilized are able to hatch into adult insects;
(b) Name the plant hormone that induces fruit ripening. (1 mark) Ethylene;
(i) Name the type of metamorphosis in the above specimen. (1 mark)
Complete metarmophosis;
(ii) Give any two advantages of the above metamorphosis. (2 marks)
Each stage occupies a different ecological niche; hence there’s no competition for resources e.g food;
– Many stomata
(ii) Name the cell organelle in which Carbon (IV) oxide combines with water to form a complex organic compound takes place (1 mark)
Chloroplast
(a) Which factor was being investigated in the experiment? (1 mark)
Light;
(b) Which food test was carried out? (1 mark)
Starch test;
(c) State the results of the food test. (1 mark)
Starch absent/Iodine retains its brown colour/starch test negative;
Water vapour accumulates in the pits reducing water vapour diffusion gradient hence reduced transpiration rate;
Reduces permeability of the leaf to water thus reducing water loss;
The leaves expose a smaller surface area to the sun thus reducing excessive water;
Parenchyma cells;
Xylem vessels;
Stimulates the synthesis and maturation of sperms;
Aquatic plants in water absorb the pesticides that drain into water bodies and so accumulate ,fish consume small quantities every time the ingest the water this also accumulates in the fish with time, as the birds continue feeding the contaminated fish they pesticides increase in levels
State the biological significance of the stage represented on the diagram above (1mark)
The exchange of DNA hence increases genetic variation;
It is a condition where pollen grains from the anthers cannot grow on the stigma of the same flower of plant/ are incompatible to stigma of the same plant/flower;
Is a condition of having different arrangements of style and stigma i.e. shorter stamen than pistil;
c)Protogyny
it’s a condition where the female matures an its ready to receive the pollen grains before the male parts mature;
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