Answer all the questions in the spaces provided(100mks)
b.Name the process by which water molecules are split by light during photosynthesis (1mk)
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A:10% B 15% C 25% D 35%
b.Name the structures on an enzyme where substrate molecules fix themselves during an enzyme reaction.(1mk)
c.State what would happen to an enzyme molecule if the temperature is:-
ii.Lowered below 10˚c.(1mk)
b.What is the main function of monosaccharide in organisms?(1mk)
b.When onion epidermal cells were placed and focused along the diameter of the field of view ,10 cells were viewed and counted. Calculate the length of each epidermal cell in micrometers (1mm = 1000micrometers).Assume the diameter of field of view= 3mm(2mks)
a.Vitamins A(1mk)
b.Vitamin D (1mk)
c.Vitamin B1 (1mk)
b.State two functions of the colon during digestion.(2mks)
b.(i) Write the dental formula of an adult human.(1mk)
ii)Work out the total number of teeth from the formula above.(1mk)
The set up was kept in sunlight for three hours after which a food test was carried out on the leaf.
b.Name the gap between incisors and premolars in some herbivores and state its function.(2mks)
b.State four factors that affect active transpiration.(4mks)
b.Diaphragm(1mk)
c.Condenser(1mk)
b.Photolysis(1mk)
b.Plasmolysis(1mk)
D- strips becomes shorter and flexible. (1mk)
b.Potassium permanganate ions /particles are at a higher concentration in the visking tubing ;
hence they diffuse through the semi permeable visking tubing ; to distilled water
making the water to turn purple.3mks)
-pH
– Chemical inhibitors
-substrate concentration
-enzyme concentration (any 3=3mks)
b.Active sites;(1mk)
c.i) it would be denatured (1mk)
b.Concentartion of carbon(iv) oxide /temperature /light intensity(1mk)
b.To store gases /to allow gaseous exchange(1mk)
c.for gaseous exchange(1mk)
-temperature
-Pressure – agitation /shaking
-size of the particles.(3mks) – thickness of membrane
-they form sweet solutions
– can crystallize (any 2 2mks
b.are a source of energy (1mk)
length of actual object
acc.width for length
b.Magnification = eye piece lens magnification x objective lens magnification (1mk)
-ability to freely interbreed and produce fertile offspring;
Reducing sugar = add about 2cm3 of Benedicts solution to the test substances ;heat to boil; colour changes from due – green- yellow –orange ; confirming presence of reducing sugar;(4mks)
b.Golgi bodies(1mk)
b.Species(1mk)
b.3mm = 3000 micrometers
= 3000 = 300 micrometers 2mks
10
b.protoctista/protista(1mk)
c.Fungi(1mk)
b.Rickets ;(1mk)
c.Beriberi(1mk
-it is richly supplied with blood to transport digested food.
-it is coiled to reduce the speed of flow of food and allow it to be fully digested /to occupy a smaller space/give more time for absorption
-has villi to increase surface area of absorption of food.
-it has a thin epithelium to allow faster diffusion of food molecule 1×4=4mks
b.absorption of water and mineral salts
-synthesis of vitamin K(2mks)
-periodontal disease/gingivitis
-pyorrhea (2mks)
b.i. I 2 C 1 Pm 2 M 3 (1mk)
2 1 2 3
2+1+2+3 = 8×2= 16
32
b.Test for starch /starch test/starch/starch.(1mk)
c.i)the covered part of the leaf remains brown/yellow /retains the colour of iodine(1mk)
and the uncovered part turns to blue black.(1mk)
ii.Starch was formed in the uncovered part (due to exposure to light)1mk
but no starch was formed in the covered part /due to lack of light(1mk)
iii.To destarch the leaf /prevent it from making starch /ensure o starch is in the leaf(1mk)
helps in turning of food /helps to manipulate the food.
Helps to temporary store food(1mk)
-chloroplasts are located on the upper part of the cells facing light
-they have thin walls for faster penetration of light (3mks)
b.presence of oxygen
-presence of glucose
-presence of enzyme
-presence of inhibitors
-temperature
regulates the amount of light passing through the condenser(1mk)
Division
Class
Order(4mks)
NB: Stop marking when the order is wrong.
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