FORM 3 BIOLOGY PAPER 2
END OF TERM 2
Answer all the questions in SECTION A in the spaces provided.
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SECTION A (40MKS)
A –
B –
(ii) State the function of structure B. (1mk)
(ii) What is the other name for the second trophic level (1mk)
A –
B –
A –
B –
Ammonia enzymes Organic compound Q + water
Carbon (IV) Oxide
SECTION B (40MKS)
Question 6 (Compulsory) and either question 7 or 8.
| Months | J | F | M | A | M | J | J | A | S | O | N | D |
| Number of locusts | 90 | 20 | 11 | 25 | 200 | 450 | 652 | 15 | 10 | 35 | 192 | 456 |
| Number of crows(birds) | 4 | 2 | 0 | 1 | 8 | 16 | 22 | 2 | 1 | 1 | 5 | 15 |
| Amount of rainfall | 20 | 0 | 55 | 350 | 520 | 400 | 350 | 10 | 25 | 190 | 256 | 350 |
(ii) Account for the relationship you have stated in (b) (i) above (1mk)
March ? Give a reason. 2mks)
Locusts –
Crows –
(ii) Construct a simple complete food chain involving these organisms (2mks).
(i)Biomass
(ii)Ecosystem
FORM 3 BIOLOGY PP 2 MARKING SCHEME
END OF TERM 2
1(a)(i) A – Nucleus
C – Cell wall
(ii) – Maintain the shape of the cell;
(b) Hypotonic solution / dilute solution / dilute sugar / salt solution.
(c) The potato cell sap was lowly concentrated than the surrounding solution; hence lost
water molecules by osmosis (through semi-permeable membrane) to become plasmolysed.
(d) – Opening and closing of stomata.
– Absorption of water by root hairs.
– Absorption of water in intestines.
– Reabsorption of water in kidney nephron. (any 2)
– Feeding in insectivorous plants.
– Movement of water from cell to cell.
– Osmoregulation.
2(a) Cartepillars
Mice each (1/2 mk)
Slugs
(b)(i) Plants Cartepillars Insectivorous hawks ;
Birds
(ii) Plants Slugs Frogs Snakes Hawks (any 1)
Plants Aphids Beetles Insectivorous Hawks
Plants
(c)(i) Largest Biomass – plants
Directly obtain energy from the sun.
(ii) Least biomass – Hawks
3(a) A – Villus
B – Lacteal
(b) A – Increases surface area for maximum digestion and absorption.
B – Absorption of fatty acids and glycerol.
(c) – Final digestion of food.
– Absorption of soluble products of digestion.
(d) Produces bile juice which contain bile salts that emulsify fats; and neutralizes the acidic chyme from the stomach;
4(a) Deamination
(b) Liver
(c) – Removal of excess amino acids.
– Availing of energy in the body. (any 1)
– Formation of glycogen / fats for storage.
(award any one)
(d) Urea
(e) It is transported to the kidney where it is excreted.
(f) (i) Diabetes inspidus
(ii) Antidiuretic Hormone / Vasopressin
(iii) Pituitary gland.
5(a) To remove / expel dissolved air from the glucose solution.
(b) To prevent entry of oxygen into the yeast – glucose solution.
(c) Anaerobic respiration.
(d) Becomes white precipitate.
(e) High temperature kills the yeast cells; hence the reaction stops;
(f) – Making of beer / Brewing / Ethanol / Alcohol.
– Baking industry / Raising of the dough. (any 2)
6(a)
Scale (x and y – axis) (2mks)
Curve plotting – each (1mk) total 2mks
Curve labeling – each (1mk) total 2mks
(b)(i)The population of locusts increase with increase in the amount of rainfall.
(ii)Increased amount of food;
Improved breeding conditions;
Less food availability to locusts and crows.
Crows – Secondary consumers
(ii) Grass Locusts Crows
crows would reduce
interactions lead to a self-sustaining system.
Hydrophytes
When body temperature is low below normal:
Less blood flow to the skin; reduces heat loss / more heat is retained in the body;
(20mks)
(;) means a marking point.
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